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30a^2+24a-6=0
a = 30; b = 24; c = -6;
Δ = b2-4ac
Δ = 242-4·30·(-6)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-36}{2*30}=\frac{-60}{60} =-1 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+36}{2*30}=\frac{12}{60} =1/5 $
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